How much K-Pam HL (metam sodium) is required for treating 12.88 acres at 30 gallons per acre?

To determine the amount of K-Pam HL (metam sodium) needed for treating 12.88 acres at a rate of 30 gallons per acre, you multiply the number of acres by the gallons required per acre.

The calculation is straightforward:

12.88 acres × 30 gallons per acre = 386.4 gallons.

This amount represents the total quantity of K-Pam HL required for the treatment of the specified area. Therefore, the correct answer is 386.4 gallons. Other options do not match this calculated requirement based on the provided treatment rate.